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JavaScript

JR Lee
JR Lee
4,970 Points
Posted by JR Lee
JR Lee
4,970 Points

( 0 == "b" ) returning false, but it should be true?

Hi, I tried running ( 0 == "b" ) in console, and it returns false, but as the link "Why JavaScript treats 0 equal to an empty string" in the teacher's notes explains, using == operator on a comparison with 2 different operands, if one of the operands is a number, the other operand would convert to a number, in this case b should convert to a number by default, which should be 0. Can someone please explain why then ( 0 == "b" ) would log false? Thank you!

1 Answer

Steven Parker
Steven Parker
231,007 Points
Steven Parker
Steven Parker
231,007 Points

The string would be converted to a number if it contains only digits. So for example, 0 == "0" would be true.

But since "b" isn't a digit, and is also not an empty string, it cannot be converted to a number and will not be equal to any number.