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Start your free trialjalil damian
1,452 PointsGreat work! OK, you're doing great so I'll keep increasing the difficulty. For this step, make an
can some one help challenge 3
# The dictionary will look something like:
# {'Andrew Chalkley': ['jQuery Basics', 'Node.js Basics'],
# 'Kenneth Love': ['Python Basics', 'Python Collections']}
#
# Each key will be a Teacher and the value will be a list of courses.
#
# Your code goes below here.
def num_teachers(teachers):
course = 0
for teacher in teachers:
course += 1
return course
def num_courses(a_dict):
total = 0
for key, value in a_dict.items():
total += len(value)
return total
3 Answers
Alexandra Barnett
Front End Web Development Techdegree Graduate 46,473 PointsHi Jalil! Great work so far!
You need to make a function and create an empty list (master list) for all the courses that will be returned at the end. The tricky bit is the for loop(s). You need to loop over the dictionary (like you did in the previous task) but, the list of courses from the value of the key/value pair cannot be added to your master list because you will have lists inside of a list. This means you need to loop over the list of courses for each teacher and then add each course individually into the master list. It results in having a for loop nested inside of another for loop like so:
def courses(a_dict):
total_courses = []
for key, value in a_dict.items():
for course in value:
total_courses.append(course)
return total_courses
That was a bit long winded but I hope some of that made some sense - let me know if you have any questions! :)
jalil damian
1,452 Pointsthank you rely again
jalil damian
1,452 Pointshey
jalil damian
1,452 Pointsjalil damian
1,452 Pointshey can you help me when i need help
jalil damian
1,452 Pointsjalil damian
1,452 Pointsok i follow you on github.com
jalil damian
1,452 Pointsjalil damian
1,452 Pointshey how do i make a dict to return name
jalil damian
1,452 Pointsjalil damian
1,452 Pointshey i need help