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Start your free trialChris Campisi
1,226 Points** must be mapping, not list error
The string used before the defined function must be filled in by members of the dictionary further above. These two need to be used to create a list with the string already filled in by the values of the dictionary. By example on the video it seems like using **my_dict should work.
dicts = [
{'name': 'Michelangelo',
'food': 'PIZZA'},
{'name': 'Garfield',
'food': 'lasanga'},
{'name': 'Walter',
'food': 'pancakes'},
{'name': 'Galactus',
'food': 'worlds'}
]
string = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(my_string, my_dict):
my_list = []
for x in my_string:
my_list.append(x.format(**my_dict))
return my_list
1 Answer
Chris Freeman
Treehouse Moderator 68,441 PointsHere is your corrected code
def string_factory(my_dict, my_string): # <-- list of dict is first parameter
my_list = []
for x in my_dict: # <-- loop through list of dicts
my_list.append(my_string.format(**x)) # <-- format using dict contents
return my_list