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Start your free trialImmanuel Jaeggi
5,164 PointsA Challenge question
It tells me,
'The items in the array weren't logged out in order. Your should log all the temperatures in order, starting at 100 and ending at 10.'
Any suggestions?
var temperatures = [100,90,99,80,70,65,30,10];
for (var i = 0; i < temperatures.length; i += 1) {
console.log([i]);
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>JavaScript Loops</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
3 Answers
jamesjones21
9,260 PointsHi Immnuel,
you've done everything correct apart from declaring the variable that holds the array data:
Your code:
var temperatures = [100,90,99,80,70,65,30,10];
for (var i = 0; i < temperatures.length; i += 1) {
console.log([i]);
}
Updated Code:
var temperatures = [100,90,99,80,70,65,30,10];
for (var i = 0; i <= temperatures.length; i++) {
console.log(temperatures[i]);
}
Adam Beer
11,314 PointsYou are near. Inside the console.log() use temperatures with [i].
Immanuel Jaeggi
5,164 PointsThanks everyone! Was able to find the bug soon after...