Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

Python Python Basics (2015) Logic in Python Conditional Value

Posted by Jack Westhoven
Jack Westhoven
553 Points

A question to the Treehouse staff members

Dear Treehouse staff, It seems as if the "elif" statement in python is no longer working. when I try, it says invalid syntax. I use the examples from the questions to make sure it didnt work, and I was correct. Please help.

conditions.py 
admitted = None
Jack Westhoven
Jack Westhoven
553 Points

this error is in 3.5.0

Steven Parker
Steven Parker
231,007 Points
Steven Parker
Steven Parker
231,007 Points

It doesn't look like you've written any code yet. In particular, there's no "elif" in your code above (and, you also don't need one for that challenge).

What is the actual code that caused the error?

1 Answer

Chris Freeman
MOD
Chris Freeman
Treehouse Moderator 68,426 Points
Chris Freeman
Chris Freeman
Treehouse Moderator 68,426 Points

I've verified that an elif is syntactically allowable. The issue with this challenge is it's explicitly looking for an else not an elif in the solution.

Perhaps you're using the form:

if arg >= 50:
    result = True
elif arg < 50:
    result = False

Since the second condition is always True if the first condition is False, this can be simplified to:

if arg >= 50:
    result = True
else:
    result = False