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Python Python Collections (2016, retired 2019) Dictionaries String Formatting with Dictionaries

A quiz question!

Let's test unpacking dictionaries in keyword arguments. You've used the string .format() method before to fill in blank placeholders. If you give the placeholder a name, though, like in template below, you fill it in through keyword arguments to .format(), like this: template.format(name="Kenneth", food="tacos") Write a function named string_factory that accepts a list of dictionaries as an argument. Return a new list of strings made by using ** for each dictionary in the list and the template string provided. I tried once but couldn't help it!

string_factory.py
# Example:
# values = [{"name": "Michelangelo", "food": "PIZZA"}, {"name": "Garfield", "food": "lasagna"}]
# string_factory(values)
# ["Hi, I'm Michelangelo and I love to eat PIZZA!", "Hi, I'm Garfield and I love to eat lasagna!"]

template = "Hi, I'm {name} and I love to eat {food}!"
def string_factory(**{"name":"Aryan", "food": "Tacos"}):
    my_list=[]
    my_list=template.format(["name"] , ["food"])
    return my_list

1 Answer

Christopher Shaw
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Christopher Shaw
Python Web Development Techdegree Graduate 58,248 Points

In the values they give as an example, it is a list of dictionaries. It is a single item to import.

def string_factory(values):
    # create empty list
    new_list = []
    # Iterate dictionaries
    for val in values:
        # for visual reference, unpack dictionaries
        name = val['name']
        food = val['food']
        new_list.append(template.format(name, food))
    return new_list

Thanks a ton!

def string_factory(values): # create empty list new_list = [] # Iterate dictionaries for val in values: # for visual reference, unpack dictionaries nameD = val['name'] foodD = val['food'] new_list.append(template.format(name = nameD, food = foodD)) return new_list