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Logan Fox
Courses Plus Student 3,379 PointsAdd to the following SELECT statement to JOIN the Media table and the Genres table using the joining table Media_Genres.
I can't figure out what I am doing wrong? Can someone help?
SELECT * FROM Media WHERE JOIN media_id=3 Media_Genres ON Media.media_id = Genres.genre_id;
3 Answers
Steven Parker
243,201 PointsHere a few hints:
- a
WHEREclause would come after anyJOINclauses - the requirements don't sound like a
WHEREis needed anyway - the first thing after the
JOINkeyword should be a table name - since the instructions indicate a junction table is needed, there will be 2
JOINs
In future questions, please provide a link to the course page to facilitate an accurate answer.
Logan Fox
Courses Plus Student 3,379 PointsNo, I don't really understand how JOIN works?
Steven Parker
243,201 PointsThe basic syntax is: "JOIN table_name ON key_matching_expression". You have all these parts in your code above, but they got mixed with a WHERE clause. As I mentioned before, this challenge will require 2 joins because there are 3 tables.
Logan Fox
Courses Plus Student 3,379 PointsOK Thank you I think I got it!
Logan Fox
Courses Plus Student 3,379 PointsLogan Fox
Courses Plus Student 3,379 PointsOk I'm just not understanding how JOIN works.
https://teamtreehouse.com/library/integrating-php-with-databases/using-relational-tables/joining-tables
Steven Parker
243,201 PointsSteven Parker
243,201 PointsSo did you get it with those hints?