Welcome to the Treehouse Community

Want to collaborate on code errors? Have bugs you need feedback on? Looking for an extra set of eyes on your latest project? Get support with fellow developers, designers, and programmers of all backgrounds and skill levels here with the Treehouse Community! While you're at it, check out some resources Treehouse students have shared here.

Looking to learn something new?

Treehouse offers a seven day free trial for new students. Get access to thousands of hours of content and join thousands of Treehouse students and alumni in the community today.

Start your free trial

JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

Posted by archisha chidumalla
archisha chidumalla
142 Points

After your newly created returnValue function, create a new variable named echo. Set the value of echo to be the results

help

script.js 
function returnValue (drink) {
 var echo = drink + "is good!";
  return drink;
}
returnValue(coffee());
index.html 
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

1 Answer

Nick Budak
PLUS
Nick Budak
Courses Plus Student 12,149 Points
Nick Budak
Nick Budak
Courses Plus Student 12,149 Points

Hi Archisha,

Your var declaration is inside the returnValue() function, which means it will only exist while the function is being called. Try declaring echo outside the function so you can set it equal to the function's result:

function returnValue(drink) {
  return drink;
}

var echo = returnValue('juice');

Moderator Edit: Moved response from Comment Section to Answer section as it provides an answer.