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Arlene TIlly
1,619 PointsAjax- doing open challenge. Following workspace. Why am I getting a parse error?
I don't understand what I'm doing wrong.
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
};
var open ('GET', 'footer.html');
function sendAJAX() {
xhr.send();
document.getElementById('load').style.display = "none";
}
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
2 Answers
Will Potter
7,577 PointsThis first half of your code looks good. But I think the problem lies in the "open" and "send" stages of your request. First of all you're creating a variable called open, but open is a method that is used on the xhr request. Try this instead:
request.open('GET', 'footer.html');
Notice how I used dot notation to apply the open method to the variable request. Lastly, sending the request should be much simpler at this stage of the AJAX course. All you have to do is:
request.send();
and you should be good to go!
Arlene TIlly
1,619 PointsThank you Will. I got it finished.