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7,705 PointsAjax error : You need to specify the request object and use the open() method on it.
i don't know what i'm doing wrong ..
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
if (request.readyState === 4) {
document.getElementById("footer").innerHTML = request.responseText;
}
request.open ("GET","footer.html");
};
<!DOCTYPE html>
<html>
<head>
<meta charset="utf-8">
<title>AJAX with JavaScript</title>
<script src="app.js"></script>
</head>
<body>
<div id="main">
<h1>AJAX!</h1>
</div>
<div id="footer"></div>
</body>
</html>
1 Answer
Adam Beer
11,314 PointsYou are very close. Put it under the function. Hope this help.
jocelin queau
7,705 Pointsjocelin queau
7,705 Pointsthanks a lot ! i passed it thank to your help