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JavaScript AJAX Basics (retiring) AJAX Concepts Finish the AJAX Request

Posted by saddam lashuel
saddam lashuel
Courses Plus Student 9,178 Points

Ajax request (open method)

var request = new XMLHttpRequest(); request.onreadystatechange = function () { if (request.readyState === 4) { document.getElementById("footer").innerHTML = request.responseText; }; request.open('GET', 'footer.html'); };

I don't know why this is incorrect.

app.js 
var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  };
  request.open('GET', 'footer.html');
};
index.html 
<!DOCTYPE html>
<html>
<head>
  <meta charset="utf-8">
  <title>AJAX with JavaScript</title>
  <script src="app.js"></script>
</head>
<body>
  <div id="main">
    <h1>AJAX!</h1>
  </div>
  <div id="footer"></div>
</body>
</html>

1 Answer

Neil McPartlin
Neil McPartlin
14,662 Points
Neil McPartlin
Neil McPartlin
14,662 Points

Your 'request open' entry request.open('GET', 'footer.html'); appears one line too soon and is within the 'onReadyStateChange' function. Just switch the bottom 2 lines to correct this.

var request = new XMLHttpRequest();
request.onreadystatechange = function () {
  if (request.readyState === 4) {
    document.getElementById("footer").innerHTML = request.responseText;
  }
};
  request.open('GET', 'footer.html');
saddam lashuel
saddam lashuel
Courses Plus Student 9,178 Points

thanks!!