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Start your free trialJoe Mackey
20,418 PointsAlright, let's make this last step a bit harder and do two things. Make a copy of favorite_
I made a copy of favorite _things and called the copy sorted_things[:] then appended .sort() tired of watching the movie, what am I doing wrong here.
Thanks Joe
favorite_things = ['raindrops on roses', 'whiskers on kittens', 'bright copper kettles',
'warm woolen mittens', 'bright paper packages tied up with string',
'cream colored ponies', 'crisp apple strudels']
slice1 = favorite_things[1:4]
slice2 = favorite_things[-2:]
favorite_things = sorted_things[:].sort() # favorite_thingd = sorted_things[:] should make a copy of original list, right?
# then append .sort() should sort the new list, right?
# why does this code return Task 1 is no longer passing?
3 Answers
Chris Freeman
Treehouse Moderator 68,457 PointsThere are two errors in your code. First it seems what you really wanted was to make a copy of favorite_things
, then sort it and assign it to sorted_things
. Something like:
sorted_things = favorite_things[:].sort()
The issue with this approach is that .sort()
sorts a list in-place and returns None
. This means that the new temporary list favorite_things[:]
does get sorted in place, but it is the return value None
that gets assigned to sorted_things
.
To correct this, break the statement into two parts:
sorted_things = favorite_things[:] # sorted_things get the copy
sorted_things.sort() # sorted_things is sorted in-place
Post back if you need more help. Good Luck!!
Joe Mackey
20,418 PointsThank you sir. I had my head pointed the wrong way. But I bet I remember that kind hint. Thanks Joe
Tapiwanashe Taurayi
15,889 Pointssorted_things = favorite_things[:] # sorted_things get the copy sorted_things.sort()