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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Posted by Prashant Nayak
Prashant Nayak
2,300 Points

Alright, this one might be a bit challenging but you've been doing great so far, so I'm sure you can manage it.

Not sure of the issue here, any pointers will help

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.



def word_count(val):
    val=val.lower()
    dist={}
    list1=val.split(" ")

    for x in list1:
        if x in dist:
            dist[x] +=1

        else:
            dist[x]=1

    return dist

1 Answer

Louise St. Germain
Louise St. Germain
19,424 Points
Louise St. Germain
Louise St. Germain
19,424 Points

Hi Prashant,

It took me a while to figure out the problem, but the issue seems to be that you are splitting only on a hard-coded space (" "), whereas the challenge is expecting you to split on any whitespace (which could be " ", but could also be new lines and such).

Try removing the hard-coded space from the split statement:

# Use this:
list1=val.split()
# instead of this:
list1=val.split(" ")

That should fix it!

Prashant Nayak
Prashant Nayak
2,300 Points

gr8 thanks for your help, it worked !!