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Start your free trialPhil Ward
4,204 PointsAm i miss understanding the question about creating a new object?
step 3 of 7 details an object and asks us to create a variable and assign it to the object. What am i doing wrong here?
<?php
include("class.palprimechecker.php");
$checker = new $PalprimeChecker ();
echo "The number ## ";
echo "(is|is not)";
echo " a palprime.";
?>
1 Answer
Robert Richey
Courses Plus Student 16,352 PointsHi Phil,
You have a $
in front of the PalprimeChecker
class - PHP is reading that as a variable. Drop the $
and your code should work.