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Python Python Basics (2015) Shopping List App Continue

Bapi Roy
Bapi Roy
14,237 Points
Posted by Bapi Roy
Bapi Roy
14,237 Points

Am I missing something

def loopy(items):
    # Code goes here
    for idx, item in enumerate(items):
        if idx == 0 and 'a' in item:
            continue
        else:
            print(item)

Getting "Bummer! Try again!" in Challenge BUT working on my local shell

breaks.py 
def loopy(items):
    # Code goes here
    for idx, item in enumerate(items):
        if idx == 0 and 'a' in item:
            continue
        else:
            print(item)

3 Answers

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points
james south
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

your code does not do what the challenge asks. the enumeration gets the index of the list and each corresponding element, it does not check to see if the first letter of each element is an 'a'.

Bapi Roy
Bapi Roy
14,237 Points
Bapi Roy
Bapi Roy
14,237 Points

It is done in line

if idx == 0 and 'a' in item:
Prashant Nayak
Prashant Nayak
2,300 Points
Prashant Nayak
Prashant Nayak
2,300 Points

item[0]=='a'

Bapi Roy
Bapi Roy
14,237 Points
Bapi Roy
Bapi Roy
14,237 Points

It will not work when item is "abc"

Bapi Roy
Bapi Roy
14,237 Points
Bapi Roy
Bapi Roy
14,237 Points

@Kenneth Love Can you help me with this problem?