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Python Python Basics (2015) Shopping List App Continue

Posted by Jesse Mensah
Jesse Mensah
1,759 Points

am stuck on this challenge

same idea as the last one . My loopy function needs to skip an item this time. if character at index 0 of current item is the letter "a", continue to the next one otherwise print out current member

breaks.py 
def loopy(items):
    # Code goes here
    items:["abc", "xyz"]
        for item in items:
            if item[0] == "a":
                continue
            else:  
                print(item)

1 Answer

Ryan S
Ryan S
27,276 Points
Ryan S
Ryan S
27,276 Points

Hi Jesse,

You don't need to define "items". The list ["abc", "xyz"] is only provided as an example. If you take that line out of your code then it should work fine.

As a side note, you tried to define items using a colon. You'd need to use an equal sign if that was your intention.

Good luck.