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vijay tripathi
Courses Plus Student 693 PointsANS to this line. Inside of your foreach loop echo each of the names to the screen.
How can I write this?
<?php
$names = array('Mike', 'Chris', 'Jane', 'Bob');
foreach($names as $name) {echo "$name <br>";}
?>
1 Answer
Erik McClintock
45,783 PointsVijay,
You're so close! You have your temporary $name variable inside a string, which is what's causing your issue here.
You have:
foreach( $names as $name ) {
echo "$name <br>"; // note how $name is inside quotation marks here, i.e. inside a string datatype
}
You want:
foreach( $names as $name ) {
echo $name; // note how we have removed the quotation marks, and thus we will retrieve the value stored in the given variable
}
If you want to keep the line break after each name, you can use simple concatenation in PHP to achieve this:
foreach( $names as $name ) {
echo $name . '<br>';
}
Happy coding!
Erik
Ryan Field
Courses Plus Student 21,242 PointsRyan Field
Courses Plus Student 21,242 PointsActually, variables inside double quotes in PHP will be interpreted correctly, although it's not so great for code readability.
The problem here is the
<br>tag that you have, Vijay. It'd work fine in real code, but it's causing the challenge to fail so just remove that (and the quotes, just for good measure), and you should be good to go! :)