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Kunal Malik
767 PointsAnswer not getting accepted to the word count problem. Need to make a dictionary with keys as words and values as freq
My answer to the problem word_count.py is not getting accepted. The problem states return a dictionary with each word as keys and freq as values, if passed a string to the function.
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(s):
a = dict()
for l in s.lower().split():
if l in a.keys():
a[l]=a[l] + 1
else:
a[l]=1
return a
1 Answer
Kunal Malik
767 PointsI realized I do not need to explicitly specify .split(' ') instead just doing a .split() works.