Anyone Suggest Me ruby method to count consecutive number of 1's

def consecutive(number)
  number = number.split('')     # turns number string to an array
  array = []                    # empty array to hold all counts of consecutive ones
  number.chunk { |n|            # chunk method from enumerable module
    n == '1'                    # chunk is filtering for 'chunks' of '1' and 'chunks' of 'not 1'
                                #  example: an array of [0, 1, 1, 2, 3, 5, 1, 9] will return
                                #  [false, [0]]  [true, [1, 1]]  [false, [2, 3, 5]]  [true, [1]]  [false, [9]]
  }.each do |x|                 # we want to loop through each of the above arrays
    if x[0] == true             # we want to separate the chunks of ones which are 'true' in index position 0 
      array.push(x[1].count)    # filling the empty array with counts of ones in each chunk of ones
    end
  end
  array.sort!                   # sorts the counts in ascending order | from the above example:  [1, 2]
  puts array[-1]                # puts the last number in the array as that would be the greatest #
end