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Start your free trialMohamed Ali
2,923 Pointsapp.js
We have some JavaScript code that will cycle over list items and apply colors from an array called colors. The code will apply the first color to the first list item, the second color to the second list item and so on. But the code is not complete. On line 1 of app.js, set the variable listItems to refer to a collection. The collection should contain all list items in the unordered list element with the id of rainbow.
<!DOCTYPE html>
<html>
<head>
<title>Rainbow!</title>
</head>
<body>
<ul id="rainbow">
<li>This should be red</li>
<li>This should be orange</li>
<li>This should be yellow</li>
<li>This should be green</li>
<li>This should be blue</li>
<li>This should be indigo</li>
<li>This should be violet</li>
</ul>
<script src="js/app.js"></script>
</body>
</html>
let listItems;
const colors = ["#C2272D", "#F8931F", "#FFFF01", "#009245", "#0193D9", "#0C04ED", "#612F90"];
for(var i = 0; i < colors.length; i ++) {
listItems[i].style.color = colors[i];
}
3 Answers
Adam Pengh
29,881 Pointslet listItems = document.querySelectorAll('ul#rainbow > li');
Adam Pengh
29,881 PointsSure, querySelectorAll will select all elements that match the query. The query itself is saying select all <li> elements that are direct children of a <ul> element with id="rainbow". You don't really need the ">" sign, it just makes it a little more specific. You could just use
document.querySelectorAll('ul#rainbow li');
which would get you the same result.
Loy Yee Ko
5,814 Pointsthank you adam!
Loy Yee Ko
5,814 PointsHi Adam Pengh could you explain why ('ul#rainbow > li') please? thanks!