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1,041 PointsAssign the variable "pointy" the address of "alpha".
Im struggling to pass the 3rd challenge. 'Assign the variable "pointy" the address of "alpha".'
char *pointy; char alpha = 'k';
??? pointy = &k;
Can anyone help me with why it would pass? Thanks
char *pointy;
char alpha = 'k';
pointy = &k;
1 Answer
Martin Wildfeuer
Courses Plus Student 11,071 PointsWith your code, you are assigning the address of k
to pointy
, which does not exist, though.
With the code below, pointy
points to the address of char alpha, this should pass.
char *pointy;
char alpha = 'k';
pointy = α
Hope that helps :)