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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Mauro Y.
Mauro Y.
6,520 Points

Be sure you're lowercasing the string and splitting on all whitespace!

Don't understand this error. I lowercased and added the split in the white spaces. How this error came? Tested in my system and in the workspaces as well, in both I cannot see anything wrong.

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

new_list = []
def word_count(words):
    #lowercase the string and put in the list format
    word_list = words.lower().split(' ')
    #loop for count the words in the list
    for word in word_list:

        new_list.append(word)
        new_list.append(word_list.count(word))
    my_dict = {}

    for index, item in enumerate(new_list):
        if index % 2 == 0:
            my_dict[item] = new_list[index+1]

    return my_dict

2 Answers

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

try no argument for the split method, so myString.split(). you are splitting on the space character only, not all whitespace, which includes characters like newlines, carriage returns and line feeds.

Mauro Y.
Mauro Y.
6,520 Points

Finally working. Thanks!