Break Exercise (Objective 2 of 2)

Question

The objective is to create a break in a loop if the current item is "STOP"

This is the code I originally thought up:

def loopy(items): for things in items: print(items) if items == "STOP": break

Apparently it's wrong and I've tried a few other ideas and all of those were wrong as well. I reviewed every lesson covering functions, loops, and if statements and I still have no idea how to resolve this challenge.

breaks.py

def loopy(items):
    for things in items:
        print(items)
    if items == "STOP":
        break

Answer 1 · 2017-02-27T22:40:57Z

February 27, 2017 10:40pm

Adding on to James South's explanation, not only do you need to change your print(items) to print(things) and your "if items" to "if things", your IF statement needs to be inside the for loop.

Right now the for loop will go through and print everything. You want to make sure that the if statement comes first in the for loop. That way, every item is being checked for if it equals "stop" rather than your code where the for loops prints everything and then checks for the "STOP"

-------ANSWER BELOW-------

def loopy(items):
    for things in items:
        if things == 'STOP':
             break
        print(things)

I can't believe you can't tab on this comment thing...that's annoying

Answer 2 · 2017-02-27T22:35:52Z

February 27, 2017 10:35pm

items is the list, things are the elements in the list. the if statement needs to be in the for loop, not under it, and it should check if each thing is STOP. right now it is comparing the list to STOP.

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Albert Tomasura

Albert Tomasura

Break Exercise (Objective 2 of 2)

2 Answers

jacksonpranica

jacksonpranica

james south

james south