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Python Python Basics (2015) Shopping List App Break

John Hughes
John Hughes
2,015 Points
Posted by John Hughes
John Hughes
2,015 Points

breaks.py

Having trouble breaking out of the loop if a conditional list item exists.

breaks.py 
def loopy(items):
    for each in items:
    if str in items == "STOP":
        break
    else:
        print(items)# Code goes here

2 Answers

hamsternation
hamsternation
26,616 Points
hamsternation
hamsternation
26,616 Points

your code:

def loopy(items):
    for each in items:
    if str in items == "STOP":
        break
    else:
        print(items)

first of all, you want to print the variable each and not items. items is the list passed in, printing items will not get you the answer you want.

Your if statement should have an additional indentation since it's nested inside the for loop.

Your if statement should only test each == "STOP". If you follow your current code, here's what it would do: if str in items == "STOP" python evaluates str in items and returns False, then compares False == "STOP" and returns False again. so in the end, it prints the entire list of items back.

The revised code would look like this. Let me know if it makes sense. :)

def loopy(items):
    for each in items:
        if each == "STOP":
            break
        else:
            print(each)