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Python Python Basics (2015) Shopping List App Continue

Michelle Wood
Michelle Wood
1,667 Points
Posted by Michelle Wood
Michelle Wood
1,667 Points

breaks.py code challenge task 1 of 1

Not sure where I am off track here? Thanks in advance.

breaks.py 
def loopy(items):
    things = list(items) 
    for i in things:
        if things[0] == "a":
            continue
        elif:
            print(things[i])# Code goes here
Michelle Wood
Michelle Wood
1,667 Points
Michelle Wood
Michelle Wood
1,667 Points

here is the challenge... loopy function needs to skip an item this time, though. Loop through each item in items again. If the character at index 0 of the current item is the letter "a", continue to the next one. Otherwise, print out the current member. Example: ["abc", "xyz"] will just print "xyz".

1 Answer

__ROLLER__ Angel
__ROLLER__ Angel
25,606 Points
__ROLLER__ Angel
__ROLLER__ Angel
25,606 Points

You don't need to do that step where you make the list. The for loop will handle that for you. Also, you did an elif when you needed to do an else.

def loopy(items):
    for item in items:
        if item[0] == 'a':
            continue
        else:
            print(item)