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Android Build an Interactive Story App (Retired) Finishing the User Interface Using a Model in the Controller

Kiran Raj
Kiran Raj
1,337 Points

Build an Interactive Story

I am getting an error as cannot find symbol

LandingActivity.java
import android.os.Bundle;
import android.view.View;
import android.widget.Button;
import android.widget.EditText;

public class LandingActivity extends Activity {

    public Button mThrustButton;
    public TextView mTypeLabel;
    public EditText mPassengersField;

    public Spaceship mSpaceship;

    @Override
    public void onCreate(Bundle savedInstanceState) {
        super.onCreate(savedInstanceState);
        setContentView(R.layout.activity_landing);

        mThrustButton = (Button)findViewById(R.id.thrustButton);
        mTypeLabel = (TextView)findViewById(R.id.typeTextView);
        mPassengersField = (EditText)findViewById(R.id.passengersEditText);

        // Add your code here!
      Spaceship mSpaceship = new Spaceship();
      mSpaceship.mType = mSpaceship("FIREFLY");
    }
}
Spaceship.java
public class Spaceship {
    public String mType;
    private int mNumPassengers = 0;

    public String getType() {
      return mType;
    }

    public void setType(String type) {
      mType = type;
    }

    public int getNumPassengers() {
      return mNumPassengers;
    }

    public void setNumPassengers(int numPassengers) {
      mNumPassengers = numPassengers;
    }

    public Spaceship() {
      mType = "SHUTTLE";
    }

    public Spaceship(String type) {
      mType = type;
    }
}

2 Answers

Jon Kussmann
PLUS
Jon Kussmann
Courses Plus Student 7,254 Points
public Spaceship(String type) {
      mType = type;
    }

That is another constructor you can use to make a new object, in this case mSpaceship. It accepts a string as a parameter which will set the type.

You can use it like so:

Spaceship mSpaceship = new Spaceship("FIREFLY");

Your method of changing the type after you have created mSpaceship will not work because the mType variable is private. You cannot access it directly from the object (only through methods).