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Python Python Collections (2016, retired 2019) Slices sillyCase

Enzo Cnop
Enzo Cnop
5,157 Points
Posted by Enzo Cnop
Enzo Cnop
5,157 Points

Bummer! Couldn't find 'sillycase'. Why is this occurring? 

def sillycase(string):
    count = round(len(string)/2)
    first_half = (string[:mid]).lower()
    second_half = (string[mid:]).upper()
    return first_half + second_half

Above is my code. Why is the compiler telling me 'couldn't find sillycase'? Also, a bunch of examples in questions use various stand in figures for the "(string[:mid]).lower()" portion. Some use 'half' some use 'middle' some use 'mid'. I'm confused as to how python knows these words / if I missed something in the video that explains how you can substitute integers for other variables in the slice notation.

sillycase.py 
def sillycase(string):
    count = round(len(string)/2)
    first_half = (string[:mid]).lower()
    second_half = (string[mid:]).upper()
    return first_half + second_half

1 Answer

James Shi
James Shi
8,942 Points

mid is a variable. You want to declare mid in the first line of your function instead of count, which will fix your issue. You can always substitute an integer for a variable. The slice notation is irrelevant to whether you could use variables or not.

Enzo Cnop
Enzo Cnop
5,157 Points
Enzo Cnop
Enzo Cnop
5,157 Points

Thank you! I didn't realize you could use variables in slice notation. This was the missing piece.