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Nancy Melucci
Courses Plus Student 36,143 Points"Bummer! Try again!" doesn't help me figure out how to fix this one.
This works in my IDE and gives a correct output but doesn't work here in code challenges. The feedback is minimal. Anyone out there who can clue me in as to what I am missing?
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 2, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(mystring):
string_dict = {}
mystring = "Nobody expects the Spanish Inquisition"
mystring = mystring.lower()
for word in mytring.split():
if word in string_dict:
string_dict[word] += 1
else:
string_dict[word] = 1
return string_dict
1 Answer
Jennifer Nordell
Treehouse TeacherHi there! You're sooooo close here! So I'm going to give some hints.
- Erase this line:
mystring = "Nobody expects the Spanish Inquisition"this is overwriting what Treehouse is sending in. Treehouse will give the string to be evaluated and it comes into the function through the parameter. - You have a typo. You've typed:
for word in mytring.split():when you meant to typefor word in mystring.split():. - Your indentation is incorrect. Take a closer look at the indentation in your if/else clauses
So if I comment out that line, fix a tiny spelling error, and correct the indentation, your code passes! Your logic is spot on, it's just some tiny details that are getting in the way.
Good luck!
