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Start your free trialNoor Hafiza Binti Ibrahim
11,712 PointsBummer: Uh oh, I didn't get the correct value returned. It should have been [5, 6, 7, 9]. Instead, it was 8
# enter your code below
def pop(list, index):
try:
newlist = list.pop(index)
return newlist
except IndexError as error:
return ('Invalid Index')
1 Answer
Chris Freeman
Treehouse Moderator 68,457 PointsHey Noor Hafiza Binti Ibrahim, you are very close!
The pop()
method operates on a list in-place and returns the popped item. So newlist
will contain the popped item and list
will be the modified list. change to return list
to pass the challenge.
BTW, using the name of a built-in list
as a variable name overrides its definition locally. So list()
would no longer work with the function. Alternative names could be num_list
, list1
, etc.
Post back if you need more help. Good luck!!
Noor Hafiza Binti Ibrahim
11,712 PointsNoor Hafiza Binti Ibrahim
11,712 PointsThank you 😊