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Ruby Ruby Basics (Retired) Ruby Methods Method Returns: Part 2

Ethan Klein
Ethan Klein
733 Points
Posted by Ethan Klein
Ethan Klein
733 Points

c is a % b

I'm currently having trouble finishing this code while only having two arguments instead of three.

method.rb 
def mod(a, b)
  return ("The remainder of #{a} divided by #{b} is #{c}.");
  puts a % b
end
mod(100, 5)

2 Answers

Jason Anders
MOD
Jason Anders
Treehouse Moderator 145,860 Points
Jason Anders
Jason Anders
Treehouse Moderator 145,860 Points

To add to Andren's answer ...

You could also eliminate the c = a % b line and do the equation right inside of the interpolation.

def mod(a, b)
  return ("The remainder of #{a} divided by #{b} is #{a % b}.");
end

:dizzy:

Ethan Klein
Ethan Klein
733 Points
Ethan Klein
Ethan Klein
733 Points

Thank you for the reply. Putting it in the interpolation is very clean. :)

andren
andren
28,558 Points
andren
andren
28,558 Points

You aren't limited to only using passed in arguments in a function, you can create your own variables. You know that c is meant to hold a % b so you can just create it yourself:

def mod(a, b)
  c = a % b
  return "The remainder of #{a} divided by #{b} is #{c}."
end

You also don't need to print anything with puts to pass this task. And for the record anything below a return statement is never executed anyway, since the function stops once a return is hit.

Note that I also removed the parentheses and semicolon from your return statement, as they are not necessary.