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Start your free trialNicci Boots
3,459 PointsCall the function and display the results in an alert dialog
I'm not sure why this isn't working - does anyone see something wrong in my code?
function max(six, eight){
if (six > eight){
return six;
} else {
return eight;
}
}
alert(max(six,eight));
3 Answers
Ricardo Vargas
3,583 Pointsit is because you are using variables not defined instead of integers(numbers), javacript dont know what six is (without quotes, if it had quotes it would be a string).
Also, the paramaters of your function should be named something like number1 and number2, once the function is defined, you can put any number you want when calling the function.
change the name of the numbers for numbers.
function max(number1, number2){
if (number1 > number2){
return number1;
} else {
return number2;
}
}
alert(max( 6 , 8 ));
Let me know if I was clear.
Devin Scheu
66,191 PointsYour answer should look like this :):
function max(num1, num2) {
if (num1 > num2) {
return num1;
}
if (num1 < num2) {
return num2;
}
}
Nicci Boots
3,459 PointsYou guys are the best! It totally makes sense now - thanks so much! :)