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Chetan Jaisinghani
2,896 PointsCalling the function after it throws an error
So we throw out an error when either of the arguments passed is not a number. My question is, if we are calling the function multiple times i.e. sometimes with correct arguments and sometimes with incorrect arguments, why does the function just stop after it executes the first time? What happens to console.log statements that pass correct arguments?
2 Answers
Robert Darby
9,360 PointsFrom my understanding Javascript is designed in the way like most programming language are, that when it encounters and error it will just stop.
In that example you are specifically telling it to "Error" using the Error(); function not just print out a string that says "Error".
throw new Error('Both arguments must be numbers');
Because you are telling it that it has errored it has in turn stopped processing any further code.
If you wanted it to continue on, you would just have it print out the string 'Both arguments must be numbers' and not error using the Error(); function.
console.log('Both arguments must be numbers');
It would then continue on with all the other numbers that are in fact numbers while printing out the string when it encounters one that isn't.
More info on the error function:
https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Error
Chetan Jaisinghani
2,896 PointsThank you so much for explaining that!