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Start your free trialSuleiman Abdurozikov
2,943 Pointscan anyone help
can t figure out
def combo([1, 2, 3], 'abc'):
combo_list = [[1,2,3],'abc']
for step in enumerate(combo_list):
print([step0,step1])
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
1 Answer
Nick Osborne
4,612 PointsHi Something like this does the trick by appending the combo_list with a tuple each time....
def combo(iterable1, iterable2):
combo_list = []
count = 0
for item in iterable1:
combo_list.append((iterable1[count], iterable2[count]))
count +=1
return combo_list