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Jason Smith
8,668 PointsCan anyone help? i'm still not sure how i should go about turning a string into a list, then back again.
i can't seem to figure this out
def sillycase(silly):
silly.lower()
newlist = list(silly)
half = int(len(silly))//2
newlist.upper(half:)
2 Answers
Mark Kastelic
8,147 PointsJason, You've made a few errors here. First, no need to convert the string to a list. Then when calculating the value of half you do integer division (//) after converting the string length into an integer with int( ) (again, no need, as len will always return an integer). Finally, the string functions upper( ), lower( ) etc. . . do not take arguments. See my solution below:
def sillycase(string):
half = len(string)//2 # calculate half point in string
first_half = string[:half].lower() # use half to slice string and convert to lowercase
second_half = string[half:].upper() # use half to slice string and convert to uppercase
return first_half + second_half # concatenate half strings to return full modified string
Hope this helps
Jason Smith
8,668 Pointsthanks, that looks alot easier to understand. i didn't know len() always returned an integer, either!
Oleg Zhoglo
3,455 PointsOleg Zhoglo
3,455 PointsWhat's the difference between
/and//?Mark Kastelic
8,147 PointsMark Kastelic
8,147 PointsHi Oleg,
Division with / will return a float, while // will always return an integer (any fractional remainder is discarded, so this is not like using the math function round, which although returning an integer, will round up or down depending on the fractional remainder). Think of // as the complement to modulo division using % which only returns the remainder.