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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Haitao Huang
Haitao Huang
2,834 Points

Can anyone help me fixing this code? Thank you!

Alright, this one might be a bit challenging but you've been doing great so far, so I'm sure you can manage it. I need you to make a function named word_count. It should accept a single argument which will be a string. The function needs to return a dictionary. The keys in the dictionary will be each of the words in the string, lowercased. The values will be how many times that particular word appears in the string. Check the comments below for an example.

wordcount.py
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(argument):
    argument = argument.lower().split(" ")
    result ={}

    for keys in argument:
        result[keys] = argument.count(keys)

    print(result)

1 Answer

james south
seal-mask
.a{fill-rule:evenodd;}techdegree seal-36
james south
Front End Web Development Techdegree Graduate 33,271 Points

Close! you need to return instead of print the result, and then you will get an error about splitting on all whitespace. you are only splitting on the space character, but there are other whitespace characters like tab. remove the quotes in the argument to split to capture all whitespace characters.

Haitao Huang
Haitao Huang
2,834 Points

AWOSOME! Thank you so much!