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Python Python Basics (2015) Shopping List App Continue

Rakesh Sadasivan Pillai
PLUS
Rakesh Sadasivan Pillai
Courses Plus Student 957 Points
Posted by Rakesh Sadasivan Pillai
Rakesh Sadasivan Pillai
Courses Plus Student 957 Points

can I do the below with the list named things if (things[0] != 'a'): print ("HI")

the interpreter says there is a syntax error

breaks.py 
def loopy(items):
    # Code goes here
  for things in items:
    if (things = 'a'):
      continue
    else:
       print (things)

2 Answers

Kourosh Raeen
Kourosh Raeen
23,733 Points
Kourosh Raeen
Kourosh Raeen
23,733 Points

To do the comparison you need to use ==. Also, instead of comparing things with 'a' you nned to compare the item at index 0 of things with 'a':

if (things[0] == 'a'):