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Python Python Basics (2015) Letter Game App Even or Odd Loop

Pratham Patel
Pratham Patel
4,976 Points
Posted by Pratham Patel
Pratham Patel
4,976 Points

Can I get some help with this

I'm confused on how to make it show that its an even number

even.py 
import random

start = 5

def even_odd(num):
    # If % 2 is 0, the number is even.
    # Since 0 is falsey, we have to invert it with not.
    return not num % 2
    while start == True:
        num = random.randint(1, 99)
        if num == even_odd:
Krahr Chaudhury
Krahr Chaudhury
Courses Plus Student 139 Points
Krahr Chaudhury
Krahr Chaudhury
Courses Plus Student 139 Points

Hi,

I'm no expert on Python, but let me try and help:

Firstly, you're calling the even_odd method incorrectly. It should be:

   if even_odd(num):

I think you need to indent correctly, so the while loop is outside of the even_odd method. (i.e. everything from while should start from the left edge.

I'm not sure what you're trying to achieve in the loop, because start = 5 and not True so the loop won't run. If you wanted to check if it has a value set then you just need to do

while start:

but that would run forever. Is this what you want?

Here's a code that increments start by one after each pass and stops when it's greater than 10. (i.e. runs 5 times)

import random

start = 5

def even_odd(num):
    # another way to return even number
    return num % 2 == 0

while start and start < 10:
  num = random.randint(1, 99)
  if even_odd(num):
    print "%d is an even number" % (num)
  else:
    print "%d is an odd number" % (num)

  start += 1

print "done!"

Another thing, why is the method called even_odd? Is it python practice or shouldn't it be called is_even_number?