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1,461 PointsCan I just do pop three times?
Edit
Nevermind, I think I misunderstood the original question after reading through the community forums.
Or is there a more efficient way?
messy_list = ["a", 2, 3, 1, False, [1, 2, 3]]
# Your code goes below here
messy_list.pop(0)
messy_list.pop(0)
messy_list.pop(0)
messy_list
1 Answer
Michael Hulet
47,913 PointsNo, you shouldn't be able to just call messy_list.pop(0)
3 times. This moves the 1
to index 0
, but it also totally removes the first 3 elements of the list, which is not what you want. Instead, you can do it in 1 line by pop
ping the 1
from its index and inser
ting it at the first index. That way, the 1
gets moved to its proper spot, while all the other elements stay put