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Start your free trialJudy Tsai
6,376 PointsCan not create String pointing to array element directly
Hi,
I followed the steps to create the NSString *thang, but received
error: Semantic Issue: Initializing 'NSString *' with an expression of incompatible type 'NSArray'
The code looks like this
NSArray *foo = [[NSArray alloc] initWithObjects: @"f", @"o", @"o", nil];
NSLog(@"%@", foo);
//use for loop to print individual item in array
for (NSString *string in foo){
NSLog(@"%@", string);
}
NSString *thang = foo[2];
NSLog(@"%@", thang);
What am I missing here?
Thank you!
4 Answers
Stone Preston
42,016 Pointsmaybe try:
NSString *thang = [foo objectAtIndex:2];
Judy Tsai
6,376 PointsHi, Stone,
That worked! Thank you!
I also ran on NSMutableArray, when I declare array and assign value like this:
NSMutableArray *lots = [[NSMutableArray alloc] init];
lots[0] = @"bravo";
lots[1] = @"lima";
I got the error of
Semantic Issue: Assigning to 'NSMutableArray' from incompatible type 'NSString *'
Do I need to declare individual NSString? Am I missing something here again?
Thank you so much for your help!
Stone Preston
42,016 Pointstry creating the array as a literal and see if that makes a difference:
NSMutableArray *lots =@[];
lots[0] = @"bravo";
lots[1] = @"lima";
Judy Tsai
6,376 Pointshmm..I tried that and it now gives me an additional error at declaration:
Unexpected '@' in program
Stone Preston
42,016 Pointswhat version of xcode are you using?
literal array syntax and indexing arrays using [] was added to objective c relatively recently. so that might be your issue
Judy Tsai
6,376 PointsHi, Stone,
You were correct, I tried the same code at home, which has a newer xcode and it worked fine!
Thank you for being patient and helpful for a newbie!