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Cliff Jackson
2,887 PointsCan someone explain how 6 is achieved in this code?
$numbers = array(1,2,3,4); $total = count($numbers); $sum = 0; $loop = 0;
foreach($numbers as $number) { $loop = $loop + 1; if ($loop < $total) { $sum = $sum + $number; } }
echo $sum;
2 Answers
Patrick Marshall
13,508 PointsHi Cliff,
Sometimes, when I get stuck on bugs like this I like to write out the steps in the code on paper. Going step by step through the code and writing down my results I get to see where I may have gone wrong. When I wrote yours out. get the following:
The for loop will run 4 times.
The first time:
$number.=1, $total=4, $loop=1 -- $loop < $total, $sum = $sum(0) + $number(1) = 1.
The second time:
$number =2, $total=4, $loop=2 -- $loop < $total, $sum = $sum(1) + $number(2) = 3;
The third time:
$number=3, $total=4, $loop=3 -- $loop < $total, $sum = $sum(3) + $number(3) = 6;
The fourth time:
$number=4, $total=4, $loop=4 -- $loop == $total exit.
Hope this helps.
Cliff Jackson
2,887 PointsThanks for the reply but i still don't get this at all. the code is correct but i just don;t know how 6 is output.
Patrick Marshall
13,508 Points6 is output because on each loop you're adding $number to $sum. 1 + 2 + 3 = 6;