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Ruby

Alphonse Cuccurullo
Alphonse Cuccurullo
2,513 Points
Posted by Alphonse Cuccurullo
Alphonse Cuccurullo
2,513 Points

Can someone help me?

After your .sort! call, add an if statement. If rev is true, call reverse! on arr. Keep your numbers array and the puts statement so that you can see your work in action 

def alphabetize(arr, rev=false)
    arr.sort!
    if rev == true
     puts arr.reverse!
end
end

numbers = [1,4,5,6,7,8,55]
alphabetize(numbers)
puts numbers

Its telling me this " It looks like your method doesn't default to alphabetizing an array when it doesn't receive a second parameter."

De Ming Liu
De Ming Liu
21,774 Points
De Ming Liu
De Ming Liu
21,774 Points

You didn't add the else after the if statement.

You want something like this, so it defaults to sorting the array if the 2nd parameter isn't entered (just like it explains):

def alphabetize(arr, rev=false)
    arr.sort!
    if rev == true
     puts arr.reverse!
    else
      puts arr
    end
end


numbers = ["c", "a", "b"]
alphabetize(numbers)

Alternatively, he's a shorter way to do it:

def alphabetize(arr, rev=false)
    arr.sort!
    if rev == true then puts arr.reverse! else puts arr end
end

numbers = ["c", "g", "h"]
alphabetize(numbers, true)
Alphonse Cuccurullo
Alphonse Cuccurullo
2,513 Points
Alphonse Cuccurullo
Alphonse Cuccurullo
2,513 Points

So i did what you said and this popped up.

"It looks like your method doesn't default to alphabetizing an array when it doesn't receive a second parameter."

De Ming Liu
De Ming Liu
21,774 Points
De Ming Liu
De Ming Liu
21,774 Points

Link to the problem you're having?

De Ming Liu
De Ming Liu
21,774 Points
De Ming Liu
De Ming Liu
21,774 Points

Okay, so they actually want you to just "return" the answer in the function, not "puts" it. Use this:

def alphabetize(arr, rev=false)
    arr.sort!
    if (rev == true)
        arr.reverse!
    else
        arr
    end
end

numbers = [1, 2, 7, 3]

puts alphabetize(numbers)

Or this shorter version:

def alphabetize(arr, rev=false)
    arr.sort!
    if rev == true then arr.reverse! else arr end
end

numbers = ["c", "g", "h"]
puts alphabetize(numbers, true)

I did not include the "return" statement in the if/else statements because Ruby automatically returns the last statement, but you could add it if it helps you.

Cheers.