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Polo Moreno
11,782 Pointscan you help me in this case?
this callengue say this
Now that you've created the returnValue function, call it, by passing it a literal string value -- a series of characters in quote marks like this: 'My argument'. Store the results of the function in a variable named echo.
I write this code in my variable but the system say this, It doesn't look like you're storing the returned value in the echo variable.
who part in my code is bad
function returnValue(hello) {
return hello;
var echo = returnValue('hello');
}
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
2 Answers
Grant G
19,934 PointsYou are defining variable echo, and calling returnValue function inside returnValue function.
If you do not want to create recursive function, you should do it outside, like this:
function returnValue(hello) {
return hello;
}
var echo = returnValue('hello');
Sean T. Unwin
28,690 PointsThe var echo statement needs to be outside of the function.
function returnValue(hello) {
return hello;
}
var echo = returnValue('hello');