Cannot get any closer to answer - any help really appreciated!

Have spent about 4 hours on trying to get this to work over 2 days now and have tried it all the ways I can think of (and still not working). I am trying to .append the tuples to a list by using enumerate on an iterable but within that for loop putting another to set (in this case) the useless index equal to values in the second iterable. The output is a list of tuples, where the enumerated iterable in the first for loop is reading sequentially but the second iterable is reading the same value. Run it to see - very strange. Can anyone tell me why the script is not running? Kenneth Love

Output = [(3, 'a'), (3, 'b'), (3, 'c')]

# combo([1, 2, 3], 'abc')
# Output:
# [(1, 'a'), (2, 'b'), (3, 'c')]
# If you use .append(), you'll want to pass it a tuple of new values.
iterable_1 = [1, 2, 3]
iterable_2 = 'abc'
num_list = []

def combo(iterable_1, iterable_2):
    for index, value in enumerate(iterable_2):
        for num in iterable_1:
            index = num
        num_list.append((index, value))
    return(num_list)