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Start your free trialsasipim Suksareewattanakul
5,417 PointsCan't display multiple students with the same name. Still only show the last student with the same name only.
I used .push() to add a new object of students to a new array. I checked my new arrays and saw that the numbers of objects in there are correct based on the number of students with the same name. but when i print it out, still only print out only one record which is the last student. please help check my code!!
var message = "";
var student;
var search;
var groupStudents = [];
function print(message) {
var outputDiv = document.getElementById("output");
outputDiv.innerHTML = message;
}
function getStudentReport (student) {
var report = "<h2>Student: " + student.name + "</h2>";
report += "<p>Track: " + student.track + "</p>";
report += "<p>Achievement: " + student.achievement + "</p>";
report += "<p>Points: " + student.points + "</p>";
return report;
}
while (true) {
search = prompt("Type in the name of the student to search. Type 'quit' if you'd like to quit");
if (search === null || search.toLowerCase() === "quit") {
break;
}
for (var i = 0; i < students.length; i += 1) {
student = students[i];
if (search.toLowerCase() === student.name) {
groupStudents.push(student);
}
}
if (groupStudents.length>0) {
for (var i = 0; i < groupStudents.length; i += 1) {
message = getStudentReport(groupStudents[i]);
print(message);
}
} else {
alert("This student name " + search + " is not in our record.");
}
}
2 Answers
Tsenko Aleksiev
3,819 PointsHmm... I don't see where you define the students array? I mean you use it here "for (var i = 0; i < students.length; i += 1)" ( students.length ), but I don't see it defined anywhere...
Tsenko Aleksiev
3,819 PointsNo problem, Iām glad I helped :)
sasipim Suksareewattanakul
5,417 Pointssasipim Suksareewattanakul
5,417 PointsHi, thank you for your response. the students variable was declared in a separate js file.