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JavaScript JavaScript Loops, Arrays and Objects Simplify Repetitive Tasks with Loops Create a for Loop

Posted by Daniel Williams
Daniel Williams
Courses Plus Student 1,325 Points

Can't get the console log to show the numbers from 4 and 156.

Bummer! You need to log out EVERY number from 4 to 156 to the console. Your loop calls the console.log() method 1 times. This has been the response to the varied combinations I have tried

script.js 
var number= '';

for (var i =4; i <=156; i += 1) { 
  i += 'number' + i + 'number';
} 
console.log(number + i);

1 Answer

Emre Karakuz
Emre Karakuz
9,162 Points
Emre Karakuz
Emre Karakuz
9,162 Points

First of all, you don't need a varible name = ' ' to do this challenge

2-)You are already increasing the i value in the loop decleration with this code : ( i=4 ; i<=156; i += 1). So you dont need to increase it in the function block (between {})

3-) console.log is called after the for loop which means it will log the last i variable (156) to the console. To fix this, write console.log(i) inside the for loop.

for (var i =4; i <=156; i += 1) { 
  console.log(i);
}