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Python Python Collections (2016, retired 2019) Dictionaries Word Count

Xavi Domingo
Xavi Domingo
2,311 Points
Posted by Xavi Domingo
Xavi Domingo
2,311 Points

Can't manage to make the code work!

I've tried it in workspaces and it works, however, when I check the work it returns a Bummer!. Any idea?

wordcount.py 
# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.

def word_count(argument):

    string1 = argument.lower().split(' ')

    final_dict = {}

    for item in string1:
        if item not in final_dict:
            final_dict[item] = 1
        elif item in final_dict:
            num = final_dict[item]
            final_dict[item] = num + 1
    return final_dict

1 Answer

Krishna Pratap Chouhan
Krishna Pratap Chouhan
15,203 Points

Nothing in particular, just try split() rather than split(" ").

# E.g. word_count("I do not like it Sam I Am") gets back a dictionary like:
# {'i': 2, 'do': 1, 'it': 1, 'sam': 1, 'like': 1, 'not': 1, 'am': 1}
# Lowercase the string to make it easier.
def word_count(argument):
    string1 = argument.lower().split()
    final_dict = {}
    for item in string1:
        if item not in final_dict:
            final_dict[item] = 1
        elif item in final_dict:
            num = final_dict[item]
            final_dict[item] = num + 1
    return final_dict