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JavaScript JavaScript Basics (Retired) Creating Reusable Code with Functions Passing an Argument to a Function

can't pass it....

Hi who can help me to pass this test? thank you

script.js
function returnValue ( drink ) {
  var echo = drink;
  return echo;

}
returnValue( 'My argument' );
index.html
<!DOCTYPE HTML>
<html>
<head>
  <meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
  <title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>

1 Answer

Few problems here. First, your function has some needless code. The variable echo inside returnValue() isn't necessary, you can simply return drink;.

Second, it's asking you to place the results of the function into a variable called echo. I think this is where you got confused. Remember that this function returns a value, meaning it will send out a value when it is called. By simply running the function like this - returnValue( 'My argument' ); you're not catching the returned value from the function. You want to store its return value into something: the echo variable.

You can store results from functions using this example syntax -

var foo = myFunction('Argument');

thank you, i pass the test :-)