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Start your free trialMarco Perricone
4,831 Pointscan't pass it....
Hi who can help me to pass this test? thank you
function returnValue ( drink ) {
var echo = drink;
return echo;
}
returnValue( 'My argument' );
<!DOCTYPE HTML>
<html>
<head>
<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">
<title>JavaScript Basics</title>
</head>
<body>
<script src="script.js"></script>
</body>
</html>
1 Answer
Justin Iezzi
18,199 PointsFew problems here. First, your function has some needless code. The variable echo inside returnValue()
isn't necessary, you can simply return drink;
.
Second, it's asking you to place the results of the function into a variable called echo. I think this is where you got confused. Remember that this function returns a value, meaning it will send out a value when it is called. By simply running the function like this - returnValue( 'My argument' );
you're not catching the returned value from the function. You want to store its return value into something: the echo variable.
You can store results from functions using this example syntax -
var foo = myFunction('Argument');
Marco Perricone
4,831 PointsMarco Perricone
4,831 Pointsthank you, i pass the test :-)