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Start your free trialLee-Ann Huber
534 PointsCan't seem to answer this question right???
The Question: Check if each student has a GPA of 4.0. If the student has a GPA of 4.0, use the student's name variable to display "NAME made the Honor Roll". If not, use the variable to display "NAME has a GPA of GPA". My code is attached and it checks out making the various statements the question requires but it keeps telling me the output is wrong. I don't know how it wants me to answer this question and I can't move on with my training until I do.
<?php
$studentOneName = 'Dave';
$studentOneGPA = 3.8;
$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;
//Place your code below this comment
if ($studentOneGPA == 4.0) {
echo "$studentOneName made the Honor Roll";}
else {echo "$studentOneName has a GPA $studentOneGPA";}
if ($studentTwoGPA == 4.0) {
echo "$studentTwoName made the Honor Roll";}
else {echo "$studentTwoName has a GPA $studentTwoGPA";}
?>
1 Answer
Simon Coates
28,694 PointsTHe instruction says: If not, use the variable to display "NAME has a GPA of GPA". You're missing the word "of"