Challange solving

Question

Could you please suggest what's wrong with my code, since in preview it shows needed result but still it does not let to pass the challenge and writes " Use the variables to display...".
```index.php
<?php $studentOneName = 'Dave';
$studentOneGPA = 3.8;
$studentTwoName = 'Treasure';
$studentTwoGPA = 4.0;
//Place your code below this comment
if ( $studentOneGPA === 4.0 ) {
echo ' $studentOneName  made the Honor Role';
} else {
echo " $studentOneName has a GPA of GPA";
}
if ( $studentTwoGPA === 4.0 ) {
echo " $studentTwoName made the Honor Role";
} else {
echo " $studentTwoName has a GPA of GPA";
}
?>
```

janapozelaite · Answer

Thank you so much guys :)

Jennifer Nordell · Answer

Hi there!  @Shane Oliver (https://teamtreehouse.com/shaneoliver) is correct in one instance.  On this line you have it in single quotes so it won't expand the variable to show the value.  However, there are other issues here.  And some of them are in your strings that are being echoed out, but there's also a bug with this challenge that I reported on Friday.  You may not use the identical operator or === and make it pass.  
In the strings that you're having problems with, you have written this for example:
```php
echo " $studentTwoName has a GPA of GPA";
```
but what we want is:
```php
echo "$studentTwoName has a GPA of $studentTwoGPA";
```
You can see a solution that I posted here (https://teamtreehouse.com/community/-check-if-each-student-has-a-gpa-of-40-if-the-student-has-a-gpa-of-40-use-the-students-name-variable-to-display-na) that will show you exactly how I did it to get around the bugs (for the time being).  Hope this helps! :sparkles:

Shane Oliver · Answer

You are adding your variables as part of the string. You need need to concatenate the variables and the strings.
php
$name = 'bob';
echo $name . ' thinks fullstops to concatenate variables is pretty odd.';

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janapozelaite

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Challange solving

3 Answers

Shane Oliver

Shane Oliver

Jennifer Nordell

Jennifer Nordell

janapozelaite

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