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PHP Enhancing a Simple PHP Application Adding Search: Controller & View Accounting for Empty Results

Posted by davekenison
davekenison
14,028 Points

Challenge 3 of 3 not accepting my answer

I tested this on my localhost and it works perfectly but the code challenge won't accept my response.

<?php

    $recommendations = array();
    $recommendations[] = 'Avocado Chocolate';


?><html>
<body>

    <h1>Flavor Recommendations</h1>

  <?php
if (!empty($recommendations)) {
    echo '<ul>';
    foreach($recommendations as $flavor) { 
        echo '<li>';
        echo $flavor;
        echo '</li>';
    } 
            echo '<ul>';
} else {
 echo '<p>There are no flavor recommendations for you.</p>';
}
    ?>


</body>
</html>

1 Answer

Mike Rogers
Mike Rogers
5,280 Points
Mike Rogers
Mike Rogers
5,280 Points

Ok so the task requires you to "Let's make sure that foreach loop executes correctly if the $recommendations array is NOT empty. Add one element to the $recommendations array with a value of 'Avocado Chocolate'.".

I think the test validator runs into problems with this line:

<?php
    $recommendations = array();
    $recommendations[] = 'Avocado Chocolate';
?>

Because you've set the $recommendations variable twice (maybe, I'm probably wrong on that). I got mine to pass by using:

<?php
$recommendations = array('Avocado Chocolate');
?>
davekenison
davekenison
14,028 Points

Either syntax is correct for adding items to an array and either should work...I just figured it out. I typed my closing ul tag incorrectly. Thanks for your help, Mike!